WBJECA MCQ FOR NEW SYLLABUS
Operating System MCQ ( SET - 6)
- If the time quantum size is 2 unites of time and there is only one job of 14 time units in aready queue, the round-robin scheduling algorithm will cause ____________ context switches.
- 6
- 7
- 8
- 5
Answer: A
Explantion: None - 'Aging' is _______________________ ?
- keeping track of cache contents
- keeping track of waht pages are currently residing in memory
- increasing the priority of jobs to ensure termination in a finite time
- Both (B) and (C)
Answer: C
Explantion: None - A semaphore :
- must be accessed from only one process
- can be accessed from multiple processes
- is a binary mutex
- all of these
Answer: B
Explantion: None. - The Processor is an example of computer _____________.
- program
- software
- hardware
- none of these
Answer: C
Explantion: None - Resources are allocated to the process on non sharable basis is
- circular wait
- no premtion
- mutual exclusion
- hold and wait
Answer: C
Explantion: None - Device drivers are that ____________
- short, special purpose programs
- internal part of operating system
- both (A) and (B)
- none of above
Answer: A
Explantion: None - Usage of Pre-emption and Transaction Rollback prevents _________ ?
- Data manipulation
- Unauthorized usage of data file
- File pre-emption
- Deadlock situation
Answer: D
Explantion: None - The Process Control Block is ________
- Data Structure
- A Block In Memory
- Process Type Variable
- A Secondary Storage Section
Answer: A
Explantion: None - Simplest way of deadlock recovery is _________ ?
- preempt resource
- Lock one of the processes
- kill one of the processes
- roll back
Answer: C
Explantion: None - 10Which of the following is incorrect for virtual memory ?
- More I/O is required
- Faster and easy swapping of process
- Large programs can be writen
- More adderssable memory available
Answer: A
Explantion: None
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